1250052012133 has 4 divisors (see below), whose sum is σ = 1255282355520. Its totient is φ = 1244821668748.

The previous prime is 1250052012107. The next prime is 1250052012163. The reversal of 1250052012133 is 3312102500521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1250052012133 - 2¹⁷ = 1250051881061 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1250052012098 and 1250052012107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1250052012163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2615171335 + ... + 2615171812.

It is an arithmetic number, because the mean of its divisors is an integer number (313820588880).

Almost surely, 2^{1250052012133} is an apocalyptic number.

It is an amenable number.

1250052012133 is a deficient number, since it is larger than the sum of its proper divisors (5230343387).

1250052012133 is an equidigital number, since it uses as much as digits as its factorization.

1250052012133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5230343386.

The product of its (nonzero) digits is 1800, while the sum is 25.

Adding to 1250052012133 its reverse (3312102500521), we get a palindrome (4562154512654).

The spelling of 1250052012133 in words is "one trillion, two hundred fifty billion, fifty-two million, twelve thousand, one hundred thirty-three".