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125009959273 is a prime number
BaseRepresentation
bin111010001101100101…
…1001001100101101001
3102221200011021220121121
41310123023021211221
54022010022144043
6133232341135241
712013602056443
oct1643313114551
9387604256547
10125009959273
114901a954731
12202896ba521
13ba33122104
14609c87b493
1533b9c27ded
hex1d1b2c9969

125009959273 has 2 divisors, whose sum is σ = 125009959274. Its totient is φ = 125009959272.

The previous prime is 125009959253. The next prime is 125009959331. The reversal of 125009959273 is 372959900521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 101370281769 + 23639677504 = 318387^2 + 153752^2 .

It is a cyclic number.

It is not a de Polignac number, because 125009959273 - 213 = 125009951081 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 125009959273.

It is not a weakly prime, because it can be changed into another prime (125009959253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62504979636 + 62504979637.

It is an arithmetic number, because the mean of its divisors is an integer number (62504979637).

Almost surely, 2125009959273 is an apocalyptic number.

It is an amenable number.

125009959273 is a deficient number, since it is larger than the sum of its proper divisors (1).

125009959273 is an equidigital number, since it uses as much as digits as its factorization.

125009959273 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1530900, while the sum is 52.

The spelling of 125009959273 in words is "one hundred twenty-five billion, nine million, nine hundred fifty-nine thousand, two hundred seventy-three".