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1250113 = 5992087
BaseRepresentation
bin100110001001101000001
32100111211111
410301031001
5310000423
642443321
713424434
oct4611501
92314744
101250113
11784257
12503541
1334a017
1424781b
1519a60d
hex131341

1250113 has 4 divisors (see below), whose sum is σ = 1252800. Its totient is φ = 1247428.

The previous prime is 1250107. The next prime is 1250141. The reversal of 1250113 is 3110521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3110521 = 14892089.

It is a cyclic number.

It is not a de Polignac number, because 1250113 - 213 = 1241921 is a prime.

It is an Ulam number.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1250093 and 1250102.

It is not an unprimeable number, because it can be changed into a prime (1250173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 445 + ... + 1642.

It is an arithmetic number, because the mean of its divisors is an integer number (313200).

21250113 is an apocalyptic number.

It is an amenable number.

1250113 is a deficient number, since it is larger than the sum of its proper divisors (2687).

1250113 is an equidigital number, since it uses as much as digits as its factorization.

1250113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2686.

The product of its (nonzero) digits is 30, while the sum is 13.

The square root of 1250113 is about 1118.0845227441. The cubic root of 1250113 is about 107.7249804187.

Adding to 1250113 its reverse (3110521), we get a palindrome (4360634).

The spelling of 1250113 in words is "one million, two hundred fifty thousand, one hundred thirteen".

Divisors: 1 599 2087 1250113