Base | Representation |
---|---|
bin | 10111010010010010… |
… | …01001110100011001 |
3 | 1012021020122012201210 |
4 | 23221021021310121 |
5 | 201100331103213 |
6 | 5424300533333 |
7 | 621540235320 |
oct | 135111116431 |
9 | 35236565653 |
10 | 12501425433 |
11 | 5335801a62 |
12 | 250a851249 |
13 | 1242cc8673 |
14 | 8684650b7 |
15 | 4d27bb0c3 |
hex | 2e9249d19 |
12501425433 has 32 divisors (see below), whose sum is σ = 19142194176. Its totient is φ = 7109097408.
The previous prime is 12501425429. The next prime is 12501425441. The reversal of 12501425433 is 33452410521.
It is not a de Polignac number, because 12501425433 - 22 = 12501425429 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12501425433.
It is not an unprimeable number, because it can be changed into a prime (12501425423) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7155066 + ... + 7156812.
It is an arithmetic number, because the mean of its divisors is an integer number (598193568).
Almost surely, 212501425433 is an apocalyptic number.
It is an amenable number.
12501425433 is a deficient number, since it is larger than the sum of its proper divisors (6640768743).
12501425433 is a wasteful number, since it uses less digits than its factorization.
12501425433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3213.
The product of its (nonzero) digits is 14400, while the sum is 30.
Adding to 12501425433 its reverse (33452410521), we get a palindrome (45953835954).
The spelling of 12501425433 in words is "twelve billion, five hundred one million, four hundred twenty-five thousand, four hundred thirty-three".
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