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125021643401 is a prime number
BaseRepresentation
bin111010001101111011…
…1101110001010001001
3102221200222021112020002
41310123313232022021
54022021020042101
6133233435412345
712014103302114
oct1643367561211
9387628245202
10125021643401
1149026505136
12202915b40b5
13ba356833b5
1460a023d57b
1533bac84d6b
hex1d1bdee289

125021643401 has 2 divisors, whose sum is σ = 125021643402. Its totient is φ = 125021643400.

The previous prime is 125021643349. The next prime is 125021643413. The reversal of 125021643401 is 104346120521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 72011185801 + 53010457600 = 268349^2 + 230240^2 .

It is an emirp because it is prime and its reverse (104346120521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 125021643401 - 210 = 125021642377 is a prime.

It is a super-2 number, since 2×1250216434012 (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (125021646401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62510821700 + 62510821701.

It is an arithmetic number, because the mean of its divisors is an integer number (62510821701).

Almost surely, 2125021643401 is an apocalyptic number.

It is an amenable number.

125021643401 is a deficient number, since it is larger than the sum of its proper divisors (1).

125021643401 is an equidigital number, since it uses as much as digits as its factorization.

125021643401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 125021643401 its reverse (104346120521), we get a palindrome (229367763922).

The spelling of 125021643401 in words is "one hundred twenty-five billion, twenty-one million, six hundred forty-three thousand, four hundred one".