Base | Representation |
---|---|
bin | 111010001101111100… |
… | …1001000111110101001 |
3 | 102221200222222102111212 |
4 | 1310123321020332221 |
5 | 4022021113443101 |
6 | 133233451402505 |
7 | 12014106411503 |
oct | 1643371107651 |
9 | 387628872455 |
10 | 125022015401 |
11 | 49026739678 |
12 | 20291753435 |
13 | ba3578380a |
14 | 60a02d8d73 |
15 | 33bad0a1bb |
hex | 1d1be48fa9 |
125022015401 has 2 divisors, whose sum is σ = 125022015402. Its totient is φ = 125022015400.
The previous prime is 125022015397. The next prime is 125022015431. The reversal of 125022015401 is 104510220521.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 87521305600 + 37500709801 = 295840^2 + 193651^2 .
It is a cyclic number.
It is not a de Polignac number, because 125022015401 - 22 = 125022015397 is a prime.
It is not a weakly prime, because it can be changed into another prime (125022015431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62511007700 + 62511007701.
It is an arithmetic number, because the mean of its divisors is an integer number (62511007701).
Almost surely, 2125022015401 is an apocalyptic number.
It is an amenable number.
125022015401 is a deficient number, since it is larger than the sum of its proper divisors (1).
125022015401 is an equidigital number, since it uses as much as digits as its factorization.
125022015401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 800, while the sum is 23.
Adding to 125022015401 its reverse (104510220521), we get a palindrome (229532235922).
It can be divided in two parts, 1250220 and 15401, that added together give a palindrome (1265621).
The spelling of 125022015401 in words is "one hundred twenty-five billion, twenty-two million, fifteen thousand, four hundred one".
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