Base | Representation |
---|---|
bin | 1011010111101111001010… |
… | …0110011101100110000011 |
3 | 1122021012221111100121002202 |
4 | 2311323302212131212003 |
5 | 3114314431300002243 |
6 | 42331311301303415 |
7 | 2430161514031556 |
oct | 265736246354603 |
9 | 48235844317082 |
10 | 12502425000323 |
11 | 3a90280a7a9a5 |
12 | 149b078a04b6b |
13 | 6c8c8706a69b |
14 | 313198ccc69d |
15 | 16a33b8b74b8 |
hex | b5ef299d983 |
12502425000323 has 2 divisors, whose sum is σ = 12502425000324. Its totient is φ = 12502425000322.
The previous prime is 12502425000283. The next prime is 12502425000347. The reversal of 12502425000323 is 32300052420521.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12502425000323 - 26 = 12502425000259 is a prime.
It is not a weakly prime, because it can be changed into another prime (12502425000353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6251212500161 + 6251212500162.
It is an arithmetic number, because the mean of its divisors is an integer number (6251212500162).
Almost surely, 212502425000323 is an apocalyptic number.
12502425000323 is a deficient number, since it is larger than the sum of its proper divisors (1).
12502425000323 is an equidigital number, since it uses as much as digits as its factorization.
12502425000323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14400, while the sum is 29.
Adding to 12502425000323 its reverse (32300052420521), we get a palindrome (44802477420844).
The spelling of 12502425000323 in words is "twelve trillion, five hundred two billion, four hundred twenty-five million, three hundred twenty-three", and thus it is an aban number.
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