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125025155329 is a prime number
BaseRepresentation
bin111010001110000010…
…1000111100100000001
3102221201012212221200111
41310130011013210001
54022022414432304
6133234042551321
712014145200014
oct1643405074401
9387635787614
10125025155329
1149028493758
1220292808541
13ba36312a69
1460a08b537b
1533bb22a704
hex1d1c147901

125025155329 has 2 divisors, whose sum is σ = 125025155330. Its totient is φ = 125025155328.

The previous prime is 125025155323. The next prime is 125025155413. The reversal of 125025155329 is 923551520521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 123696407025 + 1328748304 = 351705^2 + 36452^2 .

It is a cyclic number.

It is not a de Polignac number, because 125025155329 - 215 = 125025122561 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 125025155291 and 125025155300.

It is not a weakly prime, because it can be changed into another prime (125025155323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62512577664 + 62512577665.

It is an arithmetic number, because the mean of its divisors is an integer number (62512577665).

Almost surely, 2125025155329 is an apocalyptic number.

It is an amenable number.

125025155329 is a deficient number, since it is larger than the sum of its proper divisors (1).

125025155329 is an equidigital number, since it uses as much as digits as its factorization.

125025155329 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 135000, while the sum is 40.

The spelling of 125025155329 in words is "one hundred twenty-five billion, twenty-five million, one hundred fifty-five thousand, three hundred twenty-nine".