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12503043977 is a prime number
BaseRepresentation
bin10111010010011110…
…10100111110001001
31012021100200102221212
423221033110332021
5201101234401402
65424355342505
7621560056154
oct135117247611
935240612855
1012503043977
115336707aa6
12250b2b1a35
131243444298
14868766c9b
154d29da952
hex2e93d4f89

12503043977 has 2 divisors, whose sum is σ = 12503043978. Its totient is φ = 12503043976.

The previous prime is 12503043937. The next prime is 12503044039. The reversal of 12503043977 is 77934030521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10116135241 + 2386908736 = 100579^2 + 48856^2 .

It is a cyclic number.

It is not a de Polignac number, because 12503043977 - 230 = 11429302153 is a prime.

It is a super-2 number, since 2×125030439772 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12503043937) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6251521988 + 6251521989.

It is an arithmetic number, because the mean of its divisors is an integer number (6251521989).

Almost surely, 212503043977 is an apocalyptic number.

It is an amenable number.

12503043977 is a deficient number, since it is larger than the sum of its proper divisors (1).

12503043977 is an equidigital number, since it uses as much as digits as its factorization.

12503043977 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 158760, while the sum is 41.

The spelling of 12503043977 in words is "twelve billion, five hundred three million, forty-three thousand, nine hundred seventy-seven".