125031732584453 has 4 divisors (see below), whose sum is σ = 126744496044588. Its totient is φ = 123318969124320.

The previous prime is 125031732584393. The next prime is 125031732584467. The reversal of 125031732584453 is 354485237130521.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 85308738930529 + 39722993653924 = 9236273^2 + 6302618^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-125031732584453 is a prime.

It is a super-3 number, since 3×125031732584453³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 125031732584395 and 125031732584404.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (125031732584053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 856381729958 + ... + 856381730103.

It is an arithmetic number, because the mean of its divisors is an integer number (31686124011147).

Almost surely, 2^{125031732584453} is an apocalyptic number.

It is an amenable number.

125031732584453 is a deficient number, since it is larger than the sum of its proper divisors (1712763460135).

125031732584453 is an equidigital number, since it uses as much as digits as its factorization.

125031732584453 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1712763460134.

The product of its (nonzero) digits is 12096000, while the sum is 53.

The spelling of 125031732584453 in words is "one hundred twenty-five trillion, thirty-one billion, seven hundred thirty-two million, five hundred eighty-four thousand, four hundred fifty-three".