Base | Representation |
---|---|
bin | 100101010000110… |
… | …1011000100000001 |
3 | 10020010201220120102 |
4 | 1022201223010001 |
5 | 10030041403441 |
6 | 324023052145 |
7 | 42661503251 |
oct | 11241530401 |
9 | 3203656512 |
10 | 1250341121 |
11 | 59186a877 |
12 | 2aa8a1055 |
13 | 16c06bc23 |
14 | bc0b5961 |
15 | 74b8169b |
hex | 4a86b101 |
1250341121 has 2 divisors, whose sum is σ = 1250341122. Its totient is φ = 1250341120.
The previous prime is 1250341067. The next prime is 1250341139. The reversal of 1250341121 is 1211430521.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 821395600 + 428945521 = 28660^2 + 20711^2 .
It is a cyclic number.
It is not a de Polignac number, because 1250341121 - 222 = 1246146817 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1250341093 and 1250341102.
It is not a weakly prime, because it can be changed into another prime (1250341621) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 625170560 + 625170561.
It is an arithmetic number, because the mean of its divisors is an integer number (625170561).
Almost surely, 21250341121 is an apocalyptic number.
It is an amenable number.
1250341121 is a deficient number, since it is larger than the sum of its proper divisors (1).
1250341121 is an equidigital number, since it uses as much as digits as its factorization.
1250341121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 240, while the sum is 20.
The square root of 1250341121 is about 35360.1629096926. The cubic root of 1250341121 is about 1077.3153258257.
Adding to 1250341121 its reverse (1211430521), we get a palindrome (2461771642).
The spelling of 1250341121 in words is "one billion, two hundred fifty million, three hundred forty-one thousand, one hundred twenty-one".
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