Base | Representation |
---|---|
bin | 1011010111110011001101… |
… | …1001100101010011000100 |
3 | 1122021022202021000011112222 |
4 | 2311330303121211103010 |
5 | 3114324143102034134 |
6 | 42332011214431512 |
7 | 2430230454425066 |
oct | 265746331452304 |
9 | 48238667004488 |
10 | 12503512143044 |
11 | 3a9078970335a |
12 | 149b320b02598 |
13 | 6c90cb3690c0 |
14 | 31325d441736 |
15 | 16a3a205da2e |
hex | b5f336654c4 |
12503512143044 has 48 divisors (see below), whose sum is σ = 24810669266880. Its totient is φ = 5465771395200.
The previous prime is 12503512142963. The next prime is 12503512143061. The reversal of 12503512143044 is 44034121530521.
It is a super-2 number, since 2×125035121430442 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12503512142995 and 12503512143013.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2440382 + ... + 5564394.
It is an arithmetic number, because the mean of its divisors is an integer number (516888943060).
Almost surely, 212503512143044 is an apocalyptic number.
It is an amenable number.
12503512143044 is a deficient number, since it is larger than the sum of its proper divisors (12307157123836).
12503512143044 is a wasteful number, since it uses less digits than its factorization.
12503512143044 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3128100 (or 3128098 counting only the distinct ones).
The product of its (nonzero) digits is 57600, while the sum is 35.
Adding to 12503512143044 its reverse (44034121530521), we get a palindrome (56537633673565).
The spelling of 12503512143044 in words is "twelve trillion, five hundred three billion, five hundred twelve million, one hundred forty-three thousand, forty-four".
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