12504102433 has 12 divisors (see below), whose sum is σ = 13164308244. Its totient is φ = 11872380000.

The previous prime is 12504102367. The next prime is 12504102487. The reversal of 12504102433 is 33420140521.

12504102433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 2 ways, for example, as 3721976064 + 8782126369 = 61008^2 + 93713^2 .

It is not a de Polignac number, because 12504102433 - 2⁹ = 12504101921 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12504102398 and 12504102407.

It is not an unprimeable number, because it can be changed into a prime (12504102493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 71818 + ... + 173683.

It is an arithmetic number, because the mean of its divisors is an integer number (1097025687).

Almost surely, 2^12504102433 is an apocalyptic number.

It is an amenable number.

12504102433 is a deficient number, since it is larger than the sum of its proper divisors (660205811).

12504102433 is an equidigital number, since it uses as much as digits as its factorization.

12504102433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 245616 (or 245585 counting only the distinct ones).

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 12504102433 its reverse (33420140521), we get a palindrome (45924242954).

The spelling of 12504102433 in words is "twelve billion, five hundred four million, one hundred two thousand, four hundred thirty-three".