Base | Representation |
---|---|
bin | 10010001100100010111… |
… | …110010101111101001101 |
3 | 11102112120002001212112212 |
4 | 102030202332111331031 |
5 | 130441331044020331 |
6 | 2354234104240205 |
7 | 156224425524164 |
oct | 22144276257515 |
9 | 4375502055485 |
10 | 1250422251341 |
11 | 44233484289a |
12 | 18240ba70065 |
13 | 90bb698a0a3 |
14 | 44740d723db |
15 | 227d668bd2b |
hex | 12322f95f4d |
1250422251341 has 8 divisors (see below), whose sum is σ = 1316470665120. Its totient is φ = 1184397509232.
The previous prime is 1250422251329. The next prime is 1250422251349. The reversal of 1250422251341 is 1431522240521.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1250422251341 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1250422251298 and 1250422251307.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1250422251349) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5809430 + ... + 6020823.
It is an arithmetic number, because the mean of its divisors is an integer number (164558833140).
Almost surely, 21250422251341 is an apocalyptic number.
It is an amenable number.
1250422251341 is a deficient number, since it is larger than the sum of its proper divisors (66048413779).
1250422251341 is a wasteful number, since it uses less digits than its factorization.
1250422251341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11835835.
The product of its (nonzero) digits is 19200, while the sum is 32.
Adding to 1250422251341 its reverse (1431522240521), we get a palindrome (2681944491862).
The spelling of 1250422251341 in words is "one trillion, two hundred fifty billion, four hundred twenty-two million, two hundred fifty-one thousand, three hundred forty-one".
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