Base | Representation |
---|---|
bin | 1011011000000010101111… |
… | …1011110000111000010011 |
3 | 1122021201111212001101020002 |
4 | 2312000223323300320103 |
5 | 3114411213023243242 |
6 | 42333541050040215 |
7 | 2430436005401531 |
oct | 266005373607023 |
9 | 48251455041202 |
10 | 12507681852947 |
11 | 3a925293710a6 |
12 | 14a00a541906b |
13 | 6c961419aa78 |
14 | 313537131151 |
15 | 16a548158432 |
hex | b602bef0e13 |
12507681852947 has 2 divisors, whose sum is σ = 12507681852948. Its totient is φ = 12507681852946.
The previous prime is 12507681852901. The next prime is 12507681853003. The reversal of 12507681852947 is 74925818670521.
12507681852947 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12507681852947 - 214 = 12507681836563 is a prime.
It is not a weakly prime, because it can be changed into another prime (12507681854947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6253840926473 + 6253840926474.
It is an arithmetic number, because the mean of its divisors is an integer number (6253840926474).
Almost surely, 212507681852947 is an apocalyptic number.
12507681852947 is a deficient number, since it is larger than the sum of its proper divisors (1).
12507681852947 is an equidigital number, since it uses as much as digits as its factorization.
12507681852947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 67737600, while the sum is 65.
The spelling of 12507681852947 in words is "twelve trillion, five hundred seven billion, six hundred eighty-one million, eight hundred fifty-two thousand, nine hundred forty-seven".
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