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12510143011 is a prime number
BaseRepresentation
bin10111010011010100…
…11010001000100011
31012021212001010000001
423221222122020203
5201110044034021
65425211440431
7622004314102
oct135152321043
935255033001
1012510143011
11533a716673
122511756117
131244a5b5b2
14869694039
154d343e091
hex2e9a9a223

12510143011 has 2 divisors, whose sum is σ = 12510143012. Its totient is φ = 12510143010.

The previous prime is 12510142921. The next prime is 12510143053. The reversal of 12510143011 is 11034101521.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12510143011 - 211 = 12510140963 is a prime.

It is a super-2 number, since 2×125101430112 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12510143011.

It is not a weakly prime, because it can be changed into another prime (12510149011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6255071505 + 6255071506.

It is an arithmetic number, because the mean of its divisors is an integer number (6255071506).

Almost surely, 212510143011 is an apocalyptic number.

12510143011 is a deficient number, since it is larger than the sum of its proper divisors (1).

12510143011 is an equidigital number, since it uses as much as digits as its factorization.

12510143011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 19.

Adding to 12510143011 its reverse (11034101521), we get a palindrome (23544244532).

The spelling of 12510143011 in words is "twelve billion, five hundred ten million, one hundred forty-three thousand, eleven".