Base | Representation |
---|---|
bin | 1011011000001100110000… |
… | …0110011010101000111001 |
3 | 1122021222110010101120222202 |
4 | 2312003030012122220321 |
5 | 3114432213430444433 |
6 | 42335103440555545 |
7 | 2430562414643504 |
oct | 266031406325071 |
9 | 48258403346882 |
10 | 12510368999993 |
11 | 3a93688179487 |
12 | 14a0715322bb5 |
13 | 6c9951b041c7 |
14 | 31370dd7a13b |
15 | 16a653eeeee8 |
hex | b60cc19aa39 |
12510368999993 has 2 divisors, whose sum is σ = 12510368999994. Its totient is φ = 12510368999992.
The previous prime is 12510368999983. The next prime is 12510369000023. The reversal of 12510368999993 is 39999986301521.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6517997923369 + 5992371076624 = 2553037^2 + 2447932^2 .
It is a cyclic number.
It is not a de Polignac number, because 12510368999993 - 212 = 12510368995897 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12510368999993.
It is not a weakly prime, because it can be changed into another prime (12510368999983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6255184499996 + 6255184499997.
It is an arithmetic number, because the mean of its divisors is an integer number (6255184499997).
Almost surely, 212510368999993 is an apocalyptic number.
It is an amenable number.
12510368999993 is a deficient number, since it is larger than the sum of its proper divisors (1).
12510368999993 is an equidigital number, since it uses as much as digits as its factorization.
12510368999993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 255091680, while the sum is 74.
The spelling of 12510368999993 in words is "twelve trillion, five hundred ten billion, three hundred sixty-eight million, nine hundred ninety-nine thousand, nine hundred ninety-three".
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