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12511120050 = 232521113199977
BaseRepresentation
bin10111010011011100…
…01000101010110010
31012021220212202020200
423221232020222302
5201110321320200
65425244420030
7622015523442
oct135156105262
935256782220
1012511120050
115340223740
122511b47616
131245011220
1486986a122
154d3583800
hex2e9b88ab2

12511120050 has 288 divisors, whose sum is σ = 39728707200. Its totient is φ = 2782771200.

The previous prime is 12511120033. The next prime is 12511120051. The reversal of 12511120050 is 5002111521.

12511120050 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (12511120051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 12805162 + ... + 12806138.

It is an arithmetic number, because the mean of its divisors is an integer number (137946900).

Almost surely, 212511120050 is an apocalyptic number.

12511120050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 12511120050, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19864353600).

12511120050 is an abundant number, since it is smaller than the sum of its proper divisors (27217587150).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12511120050 is a wasteful number, since it uses less digits than its factorization.

12511120050 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1218 (or 1210 counting only the distinct ones).

The product of its (nonzero) digits is 100, while the sum is 18.

Adding to 12511120050 its reverse (5002111521), we get a palindrome (17513231571).

It can be divided in two parts, 125111 and 20050, that added together give a square (145161 = 3812).

The spelling of 12511120050 in words is "twelve billion, five hundred eleven million, one hundred twenty thousand, fifty".