12511143114313 has 2 divisors, whose sum is σ = 12511143114314. Its totient is φ = 12511143114312.

The previous prime is 12511143114307. The next prime is 12511143114341. The reversal of 12511143114313 is 31341134111521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8091595552329 + 4419547561984 = 2844573^2 + 2102272^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12511143114313 is a prime.

It is a super-3 number, since 3×12511143114313³ (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (12511143114913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6255571557156 + 6255571557157.

It is an arithmetic number, because the mean of its divisors is an integer number (6255571557157).

Almost surely, 2^{12511143114313} is an apocalyptic number.

It is an amenable number.

12511143114313 is a deficient number, since it is larger than the sum of its proper divisors (1).

12511143114313 is an equidigital number, since it uses as much as digits as its factorization.

12511143114313 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4320, while the sum is 31.

Adding to 12511143114313 its reverse (31341134111521), we get a palindrome (43852277225834).

The spelling of 12511143114313 in words is "twelve trillion, five hundred eleven billion, one hundred forty-three million, one hundred fourteen thousand, three hundred thirteen".