12511333453 has 4 divisors (see below), whose sum is σ = 12515799808. Its totient is φ = 12506867100.

The previous prime is 12511333451. The next prime is 12511333511. The reversal of 12511333453 is 35433311521.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35433311521 = 23497 ⋅1507993.

It is a cyclic number.

It is not a de Polignac number, because 12511333453 - 2¹ = 12511333451 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12511333451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2228973 + ... + 2234578.

It is an arithmetic number, because the mean of its divisors is an integer number (3128949952).

Almost surely, 2^12511333453 is an apocalyptic number.

It is an amenable number.

12511333453 is a deficient number, since it is larger than the sum of its proper divisors (4466355).

12511333453 is an equidigital number, since it uses as much as digits as its factorization.

12511333453 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4466354.

The product of its digits is 16200, while the sum is 31.

Adding to 12511333453 its reverse (35433311521), we get a palindrome (47944644974).

The spelling of 12511333453 in words is "twelve billion, five hundred eleven million, three hundred thirty-three thousand, four hundred fifty-three".