125113433 has 2 divisors, whose sum is σ = 125113434. Its totient is φ = 125113432.

The previous prime is 125113411. The next prime is 125113477. The reversal of 125113433 is 334311521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 94731289 + 30382144 = 9733^2 + 5512^2 .

It is an emirp because it is prime and its reverse (334311521) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-125113433 is a prime.

It is a super-2 number, since 2×125113433² = 31306742234090978, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 125113399 and 125113408.

It is not a weakly prime, because it can be changed into another prime (125113403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62556716 + 62556717.

It is an arithmetic number, because the mean of its divisors is an integer number (62556717).

Almost surely, 2^125113433 is an apocalyptic number.

It is an amenable number.

125113433 is a deficient number, since it is larger than the sum of its proper divisors (1).

125113433 is an equidigital number, since it uses as much as digits as its factorization.

125113433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1080, while the sum is 23.

The square root of 125113433 is about 11185.4116151351. The cubic root of 125113433 is about 500.1511982736.

Adding to 125113433 its reverse (334311521), we get a palindrome (459424954).

The spelling of 125113433 in words is "one hundred twenty-five million, one hundred thirteen thousand, four hundred thirty-three".