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125118280381681 is a prime number
BaseRepresentation
bin11100011100101101011110…
…101010000011010011110001
3121102000012011002022002222201
4130130231132222003103301
5112344414214234203211
61122034313340303201
735232332424460246
oct3434553652032361
9542005132262881
10125118280381681
11369594014a3124
1212048916b41b01
1354a77ac350262
1422c7a8560b5cd
15e6e930da10c1
hex71cb5ea834f1

125118280381681 has 2 divisors, whose sum is σ = 125118280381682. Its totient is φ = 125118280381680.

The previous prime is 125118280381571. The next prime is 125118280381723. The reversal of 125118280381681 is 186183082811521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 93202785997281 + 31915494384400 = 9654159^2 + 5649380^2 .

It is a cyclic number.

It is not a de Polignac number, because 125118280381681 - 233 = 125109690447089 is a prime.

It is a super-2 number, since 2×1251182803816812 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (125118280381181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62559140190840 + 62559140190841.

It is an arithmetic number, because the mean of its divisors is an integer number (62559140190841).

Almost surely, 2125118280381681 is an apocalyptic number.

It is an amenable number.

125118280381681 is a deficient number, since it is larger than the sum of its proper divisors (1).

125118280381681 is an equidigital number, since it uses as much as digits as its factorization.

125118280381681 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1474560, while the sum is 55.

The spelling of 125118280381681 in words is "one hundred twenty-five trillion, one hundred eighteen billion, two hundred eighty million, three hundred eighty-one thousand, six hundred eighty-one".