Base | Representation |
---|---|
bin | 1011011000010100101111… |
… | …1011111111011010110011 |
3 | 1122022011222121010012212101 |
4 | 2312011023323333122303 |
5 | 3120001112010010312 |
6 | 42340100334241231 |
7 | 2430666520013155 |
oct | 266051373773263 |
9 | 48264877105771 |
10 | 12512513750707 |
11 | 3a945888a2433 |
12 | 14a1013656217 |
13 | 6c9c04260079 |
14 | 313874b54ad5 |
15 | 16a72c456a57 |
hex | b614beff6b3 |
12512513750707 has 2 divisors, whose sum is σ = 12512513750708. Its totient is φ = 12512513750706.
The previous prime is 12512513750689. The next prime is 12512513750713. The reversal of 12512513750707 is 70705731521521.
It is a strong prime.
It is an emirp because it is prime and its reverse (70705731521521) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12512513750707 - 215 = 12512513717939 is a prime.
It is not a weakly prime, because it can be changed into another prime (12512513750717) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6256256875353 + 6256256875354.
It is an arithmetic number, because the mean of its divisors is an integer number (6256256875354).
Almost surely, 212512513750707 is an apocalyptic number.
12512513750707 is a deficient number, since it is larger than the sum of its proper divisors (1).
12512513750707 is an equidigital number, since it uses as much as digits as its factorization.
12512513750707 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 514500, while the sum is 46.
The spelling of 12512513750707 in words is "twelve trillion, five hundred twelve billion, five hundred thirteen million, seven hundred fifty thousand, seven hundred seven".
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