Base | Representation |
---|---|
bin | 111010010001000001… |
… | …0111100111110000011 |
3 | 102221222012020100001121 |
4 | 1310202002330332003 |
5 | 4022224031012242 |
6 | 133252020213111 |
7 | 12016502040664 |
oct | 1644202747603 |
9 | 387865210047 |
10 | 125125250947 |
11 | 49079a40004 |
12 | 2030023a197 |
13 | ba50c8ac38 |
14 | 60adccd36b |
15 | 33c4ded667 |
hex | 1d220bcf83 |
125125250947 has 2 divisors, whose sum is σ = 125125250948. Its totient is φ = 125125250946.
The previous prime is 125125250891. The next prime is 125125250993. The reversal of 125125250947 is 749052521521.
It is a strong prime.
It is an emirp because it is prime and its reverse (749052521521) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 125125250947 - 219 = 125124726659 is a prime.
It is not a weakly prime, because it can be changed into another prime (125125253947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62562625473 + 62562625474.
It is an arithmetic number, because the mean of its divisors is an integer number (62562625474).
Almost surely, 2125125250947 is an apocalyptic number.
125125250947 is a deficient number, since it is larger than the sum of its proper divisors (1).
125125250947 is an equidigital number, since it uses as much as digits as its factorization.
125125250947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252000, while the sum is 43.
The spelling of 125125250947 in words is "one hundred twenty-five billion, one hundred twenty-five million, two hundred fifty thousand, nine hundred forty-seven".
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