Base | Representation |
---|---|
bin | 1011011000010100110011… |
… | …0001011100111010010011 |
3 | 1122022012000120111020001102 |
4 | 2312011030301130322103 |
5 | 3120001124101441024 |
6 | 42340101554455015 |
7 | 2431000050102443 |
oct | 266051461347223 |
9 | 48265016436042 |
10 | 12512527765139 |
11 | 3a945957a4706 |
12 | 14a101829446b |
13 | 6c9c07128c2c |
14 | 313876962123 |
15 | 16a72d7c41ae |
hex | b614cc5ce93 |
12512527765139 has 2 divisors, whose sum is σ = 12512527765140. Its totient is φ = 12512527765138.
The previous prime is 12512527765093. The next prime is 12512527765151. The reversal of 12512527765139 is 93156772521521.
12512527765139 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (93156772521521) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12512527765139 - 212 = 12512527761043 is a prime.
It is not a weakly prime, because it can be changed into another prime (12512527765039) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6256263882569 + 6256263882570.
It is an arithmetic number, because the mean of its divisors is an integer number (6256263882570).
Almost surely, 212512527765139 is an apocalyptic number.
12512527765139 is a deficient number, since it is larger than the sum of its proper divisors (1).
12512527765139 is an equidigital number, since it uses as much as digits as its factorization.
12512527765139 is an evil number, because the sum of its binary digits is even.
The product of its digits is 7938000, while the sum is 56.
The spelling of 12512527765139 in words is "twelve trillion, five hundred twelve billion, five hundred twenty-seven million, seven hundred sixty-five thousand, one hundred thirty-nine".
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