Base | Representation |
---|---|
bin | 1011011000010100110011… |
… | …0001011100111010011101 |
3 | 1122022012000120111020001210 |
4 | 2312011030301130322131 |
5 | 3120001124101441044 |
6 | 42340101554455033 |
7 | 2431000050102456 |
oct | 266051461347235 |
9 | 48265016436053 |
10 | 12512527765149 |
11 | 3a945957a4715 |
12 | 14a1018294479 |
13 | 6c9c07128c39 |
14 | 31387696212d |
15 | 16a72d7c41b9 |
hex | b614cc5ce9d |
12512527765149 has 4 divisors (see below), whose sum is σ = 16683370353536. Its totient is φ = 8341685176764.
The previous prime is 12512527765139. The next prime is 12512527765151. The reversal of 12512527765149 is 94156772521521.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 12512527765149 - 29 = 12512527764637 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12512527765139) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2085421294189 + ... + 2085421294194.
It is an arithmetic number, because the mean of its divisors is an integer number (4170842588384).
Almost surely, 212512527765149 is an apocalyptic number.
It is an amenable number.
12512527765149 is a deficient number, since it is larger than the sum of its proper divisors (4170842588387).
12512527765149 is an equidigital number, since it uses as much as digits as its factorization.
12512527765149 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4170842588386.
The product of its digits is 10584000, while the sum is 57.
The spelling of 12512527765149 in words is "twelve trillion, five hundred twelve billion, five hundred twenty-seven million, seven hundred sixty-five thousand, one hundred forty-nine".
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