Base | Representation |
---|---|
bin | 1011011000010111100010… |
… | …1000111000011111010100 |
3 | 1122022020220212022102021010 |
4 | 2312011320220320133110 |
5 | 3120004131002410213 |
6 | 42340303004452220 |
7 | 2431024224426615 |
oct | 266057050703724 |
9 | 48266825272233 |
10 | 12513263716308 |
11 | 3a94933169713 |
12 | 14a11a284a070 |
13 | 6c9cc3744cb4 |
14 | 3139065b7c0c |
15 | 16a7731e8ac3 |
hex | b6178a387d4 |
12513263716308 has 48 divisors (see below), whose sum is σ = 30139981272576. Its totient is φ = 4036468730880.
The previous prime is 12513263716307. The next prime is 12513263716357. The reversal of 12513263716308 is 80361736231521.
12513263716308 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12513263716307) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 24835660 + ... + 25334492.
It is an arithmetic number, because the mean of its divisors is an integer number (627916276512).
Almost surely, 212513263716308 is an apocalyptic number.
It is an amenable number.
12513263716308 is an abundant number, since it is smaller than the sum of its proper divisors (17626717556268).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12513263716308 is a wasteful number, since it uses less digits than its factorization.
12513263716308 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 566304 (or 566302 counting only the distinct ones).
The product of its (nonzero) digits is 1088640, while the sum is 48.
Adding to 12513263716308 its reverse (80361736231521), we get a palindrome (92874999947829).
The spelling of 12513263716308 in words is "twelve trillion, five hundred thirteen billion, two hundred sixty-three million, seven hundred sixteen thousand, three hundred eight".
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