Base | Representation |
---|---|
bin | 1011011000011000001001… |
… | …1001101100110011111010 |
3 | 1122022021100021111220212122 |
4 | 2312012002121230303322 |
5 | 3120004444420232344 |
6 | 42340331135241242 |
7 | 2431031253562034 |
oct | 266060231546372 |
9 | 48267307456778 |
10 | 12513427508474 |
11 | 3a94a07671142 |
12 | 14a1229679222 |
13 | 6ca01b662839 |
14 | 313920252c54 |
15 | 16a78279eaee |
hex | b618266ccfa |
12513427508474 has 4 divisors (see below), whose sum is σ = 18770141262714. Its totient is φ = 6256713754236.
The previous prime is 12513427508441. The next prime is 12513427508597. The reversal of 12513427508474 is 47480572431521.
12513427508474 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 7948773893449 + 4564653615025 = 2819357^2 + 2136505^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3128356877117 + ... + 3128356877120.
Almost surely, 212513427508474 is an apocalyptic number.
12513427508474 is a deficient number, since it is larger than the sum of its proper divisors (6256713754240).
12513427508474 is an equidigital number, since it uses as much as digits as its factorization.
12513427508474 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6256713754239.
The product of its (nonzero) digits is 7526400, while the sum is 53.
Adding to 12513427508474 its reverse (47480572431521), we get a palindrome (59993999939995).
The spelling of 12513427508474 in words is "twelve trillion, five hundred thirteen billion, four hundred twenty-seven million, five hundred eight thousand, four hundred seventy-four".
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