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125134381817 is a prime number
BaseRepresentation
bin111010010001010010…
…1110010001011111001
3102221222211102020020222
41310202211302023321
54022233400204232
6133252544025425
712016642460414
oct1644245621371
9387884366228
10125134381817
1149084107185
1220303302275
13ba52b37013
1460b11c8b7b
1533c5b03d12
hex1d229722f9

125134381817 has 2 divisors, whose sum is σ = 125134381818. Its totient is φ = 125134381816.

The previous prime is 125134381787. The next prime is 125134381891. The reversal of 125134381817 is 718183431521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 83015439376 + 42118942441 = 288124^2 + 205229^2 .

It is a cyclic number.

It is not a de Polignac number, because 125134381817 - 230 = 124060639993 is a prime.

It is a super-2 number, since 2×1251343818172 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (125134311817) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62567190908 + 62567190909.

It is an arithmetic number, because the mean of its divisors is an integer number (62567190909).

Almost surely, 2125134381817 is an apocalyptic number.

It is an amenable number.

125134381817 is a deficient number, since it is larger than the sum of its proper divisors (1).

125134381817 is an equidigital number, since it uses as much as digits as its factorization.

125134381817 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 161280, while the sum is 44.

The spelling of 125134381817 in words is "one hundred twenty-five billion, one hundred thirty-four million, three hundred eighty-one thousand, eight hundred seventeen".