Base | Representation |
---|---|
bin | 111010010001010100… |
… | …0001001011000110011 |
3 | 102221222212120200210211 |
4 | 1310202220021120303 |
5 | 4022234030014024 |
6 | 133253005204551 |
7 | 12016650650131 |
oct | 1644250113063 |
9 | 387885520724 |
10 | 125135001139 |
11 | 4908449a515 |
12 | 20303560757 |
13 | ba52cc2b95 |
14 | 60b130a751 |
15 | 33c5bc7594 |
hex | 1d22a09633 |
125135001139 has 2 divisors, whose sum is σ = 125135001140. Its totient is φ = 125135001138.
The previous prime is 125135001067. The next prime is 125135001179. The reversal of 125135001139 is 931100531521.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-125135001139 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 125135001139.
It is not a weakly prime, because it can be changed into another prime (125135001179) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62567500569 + 62567500570.
It is an arithmetic number, because the mean of its divisors is an integer number (62567500570).
Almost surely, 2125135001139 is an apocalyptic number.
125135001139 is a deficient number, since it is larger than the sum of its proper divisors (1).
125135001139 is an equidigital number, since it uses as much as digits as its factorization.
125135001139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4050, while the sum is 31.
The spelling of 125135001139 in words is "one hundred twenty-five billion, one hundred thirty-five million, one thousand, one hundred thirty-nine".
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