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125135001193 is a prime number
BaseRepresentation
bin111010010001010100…
…0001001011001101001
3102221222212120200212211
41310202220021121221
54022234030014233
6133253005205121
712016650650236
oct1644250113151
9387885520784
10125135001193
114908449a564
12203035607a1
13ba52cc2c07
1460b130a78d
1533c5bc75cd
hex1d22a09669

125135001193 has 2 divisors, whose sum is σ = 125135001194. Its totient is φ = 125135001192.

The previous prime is 125135001181. The next prime is 125135001253. The reversal of 125135001193 is 391100531521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 99444361104 + 25690640089 = 315348^2 + 160283^2 .

It is a cyclic number.

It is not a de Polignac number, because 125135001193 - 213 = 125134993001 is a prime.

It is a super-2 number, since 2×1251350011932 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (125135061193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62567500596 + 62567500597.

It is an arithmetic number, because the mean of its divisors is an integer number (62567500597).

Almost surely, 2125135001193 is an apocalyptic number.

It is an amenable number.

125135001193 is a deficient number, since it is larger than the sum of its proper divisors (1).

125135001193 is an equidigital number, since it uses as much as digits as its factorization.

125135001193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4050, while the sum is 31.

The spelling of 125135001193 in words is "one hundred twenty-five billion, one hundred thirty-five million, one thousand, one hundred ninety-three".