Base | Representation |
---|---|
bin | 1011011000011001110101… |
… | …0111110101101011001011 |
3 | 1122022022111210222010212012 |
4 | 2312012131113311223023 |
5 | 3120011411240132243 |
6 | 42340444102010135 |
7 | 2431045420000604 |
oct | 266063527655313 |
9 | 48268453863765 |
10 | 12513880005323 |
11 | 3a9511a032784 |
12 | 14a133511694b |
13 | 6ca091324b58 |
14 | 3139643a0dab |
15 | 16a7ac382d18 |
hex | b619d5f5acb |
12513880005323 has 2 divisors, whose sum is σ = 12513880005324. Its totient is φ = 12513880005322.
The previous prime is 12513880005317. The next prime is 12513880005397. The reversal of 12513880005323 is 32350008831521.
It is a weak prime.
It is an emirp because it is prime and its reverse (32350008831521) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12513880005323 - 216 = 12513879939787 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (12513880005223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6256940002661 + 6256940002662.
It is an arithmetic number, because the mean of its divisors is an integer number (6256940002662).
Almost surely, 212513880005323 is an apocalyptic number.
12513880005323 is a deficient number, since it is larger than the sum of its proper divisors (1).
12513880005323 is an equidigital number, since it uses as much as digits as its factorization.
12513880005323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 172800, while the sum is 41.
Adding to 12513880005323 its reverse (32350008831521), we get a palindrome (44863888836844).
The spelling of 12513880005323 in words is "twelve trillion, five hundred thirteen billion, eight hundred eighty million, five thousand, three hundred twenty-three".
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