Base | Representation |
---|---|
bin | 11100011101000011000011… |
… | …000110100011111100001110 |
3 | 121102002101221010222121220021 |
4 | 130131003003012203330032 |
5 | 112400304132221212304 |
6 | 1122053103432212354 |
7 | 35234112360500623 |
oct | 3435030306437416 |
9 | 542071833877807 |
10 | 125141440413454 |
11 | 36968206756853 |
12 | 120512bb23a0ba |
13 | 54a9a3061147a |
14 | 22c8c4147634a |
15 | e70339272a54 |
hex | 71d0c31a3f0e |
125141440413454 has 4 divisors (see below), whose sum is σ = 187712160620184. Its totient is φ = 62570720206726.
The previous prime is 125141440413377. The next prime is 125141440413491. The reversal of 125141440413454 is 454314044141521.
It is a semiprime because it is the product of two primes.
It is a self number, because there is not a number n which added to its sum of digits gives 125141440413454.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 31285360103362 + ... + 31285360103365.
It is an arithmetic number, because the mean of its divisors is an integer number (46928040155046).
Almost surely, 2125141440413454 is an apocalyptic number.
125141440413454 is a deficient number, since it is larger than the sum of its proper divisors (62570720206730).
125141440413454 is an equidigital number, since it uses as much as digits as its factorization.
125141440413454 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 62570720206729.
The product of its (nonzero) digits is 614400, while the sum is 43.
Adding to 125141440413454 its reverse (454314044141521), we get a palindrome (579455484554975).
The spelling of 125141440413454 in words is "one hundred twenty-five trillion, one hundred forty-one billion, four hundred forty million, four hundred thirteen thousand, four hundred fifty-four".
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