Base | Representation |
---|---|
bin | 1011011000011011101111… |
… | …0000111101101110101101 |
3 | 1122022100211100102220101020 |
4 | 2312012323300331232231 |
5 | 3120013432304032042 |
6 | 42341010435004353 |
7 | 2431064151051516 |
oct | 266067360755655 |
9 | 48270740386336 |
10 | 12514389908397 |
11 | 3a95360943483 |
12 | 14a1457a396b9 |
13 | 6ca142b66650 |
14 | 3139b1db3a0d |
15 | 16a7dc0053ec |
hex | b61bbc3dbad |
12514389908397 has 32 divisors (see below), whose sum is σ = 18557001240960. Its totient is φ = 7451625404160.
The previous prime is 12514389908387. The next prime is 12514389908411. The reversal of 12514389908397 is 79380998341521.
It is not a de Polignac number, because 12514389908397 - 214 = 12514389892013 is a prime.
It is a super-2 number, since 2×125143899083972 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12514389908387) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 23695947 + ... + 24218312.
It is an arithmetic number, because the mean of its divisors is an integer number (579906288780).
Almost surely, 212514389908397 is an apocalyptic number.
It is an amenable number.
12514389908397 is a deficient number, since it is larger than the sum of its proper divisors (6042611332563).
12514389908397 is a wasteful number, since it uses less digits than its factorization.
12514389908397 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 47914493.
The product of its (nonzero) digits is 117573120, while the sum is 69.
The spelling of 12514389908397 in words is "twelve trillion, five hundred fourteen billion, three hundred eighty-nine million, nine hundred eight thousand, three hundred ninety-seven".
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