Base | Representation |
---|---|
bin | 11100011101000101100010… |
… | …011011000000101011110110 |
3 | 121102002122211102120221110111 |
4 | 130131011202123000223312 |
5 | 112400330121004221124 |
6 | 1122054224554413234 |
7 | 35234235535212643 |
oct | 3435054233005366 |
9 | 542078742527414 |
10 | 125144113351414 |
11 | 36969358539693 |
12 | 1205192643121a |
13 | 54aa068311271 |
14 | 22c9016462dca |
15 | e70443c5e494 |
hex | 71d1626c0af6 |
125144113351414 has 12 divisors (see below), whose sum is σ = 192926699221284. Its totient is φ = 60880920007464.
The previous prime is 125144113351403. The next prime is 125144113351417. The reversal of 125144113351414 is 414153311441521.
It is a super-2 number, since 2×1251441133514142 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (125144113351417) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 22853195464 + ... + 22853200939.
It is an arithmetic number, because the mean of its divisors is an integer number (16077224935107).
Almost surely, 2125144113351414 is an apocalyptic number.
125144113351414 is a deficient number, since it is larger than the sum of its proper divisors (67782585869870).
125144113351414 is an equidigital number, since it uses as much as digits as its factorization.
125144113351414 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 45706396479 (or 45706396442 counting only the distinct ones).
The product of its digits is 115200, while the sum is 40.
Adding to 125144113351414 its reverse (414153311441521), we get a palindrome (539297424792935).
The spelling of 125144113351414 in words is "one hundred twenty-five trillion, one hundred forty-four billion, one hundred thirteen million, three hundred fifty-one thousand, four hundred fourteen".
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