Base | Representation |
---|---|
bin | 1011011000100110110110… |
… | …0010100001000110010000 |
3 | 1122022122112012122111122001 |
4 | 2312021231202201012100 |
5 | 3120041034322344202 |
6 | 42342222421323344 |
7 | 2431231105265443 |
oct | 266115542410620 |
9 | 48278465574561 |
10 | 12517372465552 |
11 | 3a9665147a849 |
12 | 14a1b4a866554 |
13 | 6ca4c9a51676 |
14 | 313bb615965a |
15 | 16a913ca0d87 |
hex | b626d8a1190 |
12517372465552 has 10 divisors (see below), whose sum is σ = 24252409152038. Its totient is φ = 6258686232768.
The previous prime is 12517372465501. The next prime is 12517372465571. The reversal of 12517372465552 is 25556427371521.
It can be written as a sum of positive squares in only one way, i.e., 7319319019776 + 5198053445776 = 2705424^2 + 2279924^2 .
It is a super-2 number, since 2×125173724655522 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12517372465493 and 12517372465502.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 391167889533 + ... + 391167889564.
Almost surely, 212517372465552 is an apocalyptic number.
It is an amenable number.
12517372465552 is a deficient number, since it is larger than the sum of its proper divisors (11735036686486).
12517372465552 is an equidigital number, since it uses as much as digits as its factorization.
12517372465552 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 782335779105 (or 782335779099 counting only the distinct ones).
The product of its digits is 17640000, while the sum is 55.
The spelling of 12517372465552 in words is "twelve trillion, five hundred seventeen billion, three hundred seventy-two million, four hundred sixty-five thousand, five hundred fifty-two".
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