12520013 has 4 divisors (see below), whose sum is σ = 13658208. Its totient is φ = 11381820.

The previous prime is 12520003. The next prime is 12520021. The reversal of 12520013 is 31002521.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31002521 = 11 ⋅2818411.

It is a cyclic number.

It is not a de Polignac number, because 12520013 - 2¹² = 12515917 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12520013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12520003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 569081 + ... + 569102.

It is an arithmetic number, because the mean of its divisors is an integer number (3414552).

Almost surely, 2^12520013 is an apocalyptic number.

It is an amenable number.

12520013 is a deficient number, since it is larger than the sum of its proper divisors (1138195).

12520013 is a wasteful number, since it uses less digits than its factorization.

12520013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1138194.

The product of its (nonzero) digits is 60, while the sum is 14.

The square root of 12520013 is about 3538.3630395990. The cubic root of 12520013 is about 232.2032317963.

Adding to 12520013 its reverse (31002521), we get a palindrome (43522534).

It can be divided in two parts, 12 and 520013, that added together give a palindrome (520025).

The spelling of 12520013 in words is "twelve million, five hundred twenty thousand, thirteen".