125200403 has 2 divisors, whose sum is σ = 125200404. Its totient is φ = 125200402.

The previous prime is 125200381. The next prime is 125200409. The reversal of 125200403 is 304002521.

It is a strong prime.

It is an emirp because it is prime and its reverse (304002521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 125200403 - 2⁸ = 125200147 is a prime.

It is a super-2 number, since 2×125200403² = 31350281822724818, which contains 22 as substring.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (125200409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62600201 + 62600202.

It is an arithmetic number, because the mean of its divisors is an integer number (62600202).

Almost surely, 2^125200403 is an apocalyptic number.

125200403 is a deficient number, since it is larger than the sum of its proper divisors (1).

125200403 is an equidigital number, since it uses as much as digits as its factorization.

125200403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 240, while the sum is 17.

The square root of 125200403 is about 11189.2985928520. The cubic root of 125200403 is about 500.2670613311.

Adding to 125200403 its reverse (304002521), we get a palindrome (429202924).

The spelling of 125200403 in words is "one hundred twenty-five million, two hundred thousand, four hundred three".