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1252015300993 is a prime number
BaseRepresentation
bin10010001110000001111…
…011010110000110000001
311102200200002200011211211
4102032001323112012001
5131003111404112433
62355100133010121
7156312051315622
oct22160173260601
94380602604754
101252015300993
11442a81aa7656
12182795483941
13910aba2b412
1444852777a49
152287b4668cd
hex12381ed6181

1252015300993 has 2 divisors, whose sum is σ = 1252015300994. Its totient is φ = 1252015300992.

The previous prime is 1252015300981. The next prime is 1252015301029. The reversal of 1252015300993 is 3990035102521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 768667767169 + 483347533824 = 876737^2 + 695232^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1252015300993 is a prime.

It is not a weakly prime, because it can be changed into another prime (1252015300973) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626007650496 + 626007650497.

It is an arithmetic number, because the mean of its divisors is an integer number (626007650497).

Almost surely, 21252015300993 is an apocalyptic number.

It is an amenable number.

1252015300993 is a deficient number, since it is larger than the sum of its proper divisors (1).

1252015300993 is an equidigital number, since it uses as much as digits as its factorization.

1252015300993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72900, while the sum is 40.

The spelling of 1252015300993 in words is "one trillion, two hundred fifty-two billion, fifteen million, three hundred thousand, nine hundred ninety-three".