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1252041005393 is a prime number
BaseRepresentation
bin10010001110000011011…
…101011001100101010001
311102200201220001002122122
4102032003131121211101
5131003134444133033
62355102451544025
7156312512643563
oct22160335314521
94380656032578
101252041005393
11442a95563762
121827a1bbb015
13910b415b119
1444855d49333
152287d842a98
hex12383759951

1252041005393 has 2 divisors, whose sum is σ = 1252041005394. Its totient is φ = 1252041005392.

The previous prime is 1252041005387. The next prime is 1252041005431. The reversal of 1252041005393 is 3935001402521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 897125325889 + 354915679504 = 947167^2 + 595748^2 .

It is a cyclic number.

It is not a de Polignac number, because 1252041005393 - 216 = 1252040939857 is a prime.

It is not a weakly prime, because it can be changed into another prime (1252041005353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626020502696 + 626020502697.

It is an arithmetic number, because the mean of its divisors is an integer number (626020502697).

Almost surely, 21252041005393 is an apocalyptic number.

It is an amenable number.

1252041005393 is a deficient number, since it is larger than the sum of its proper divisors (1).

1252041005393 is an equidigital number, since it uses as much as digits as its factorization.

1252041005393 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32400, while the sum is 35.

The spelling of 1252041005393 in words is "one trillion, two hundred fifty-two billion, forty-one million, five thousand, three hundred ninety-three".