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125213335205442 = 23111897171745537
BaseRepresentation
bin11100011110000110000000…
…010111011011011001000010
3121102100021111121201110201220
4130132012000113123121002
5112402443402303033232
61122150113451135510
735242236113236311
oct3436060027333102
9542307447643656
10125213335205442
113699574a467110
1212063224744596
1354b374a487cc3
1422cc50199c278
15e72145db342c
hex71e1805db642

125213335205442 has 16 divisors (see below), whose sum is σ = 273192731357472. Its totient is φ = 37943434910720.

The previous prime is 125213335205389. The next prime is 125213335205471. The reversal of 125213335205442 is 244502533312521.

It is a junction number, because it is equal to n+sod(n) for n = 125213335205394 and 125213335205403.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 948585872703 + ... + 948585872834.

It is an arithmetic number, because the mean of its divisors is an integer number (17074545709842).

Almost surely, 2125213335205442 is an apocalyptic number.

125213335205442 is an abundant number, since it is smaller than the sum of its proper divisors (147979396152030).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

125213335205442 is a wasteful number, since it uses less digits than its factorization.

125213335205442 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1897171745553.

The product of its (nonzero) digits is 864000, while the sum is 42.

Adding to 125213335205442 its reverse (244502533312521), we get a palindrome (369715868517963).

The spelling of 125213335205442 in words is "one hundred twenty-five trillion, two hundred thirteen billion, three hundred thirty-five million, two hundred five thousand, four hundred forty-two".

Divisors: 1 2 3 6 11 22 33 66 1897171745537 3794343491074 5691515236611 11383030473222 20868889200907 41737778401814 62606667602721 125213335205442