Base | Representation |
---|---|
bin | 1110111011010… |
… | …01111100100001 |
3 | 22201121112222222 |
4 | 13131221330201 |
5 | 224023330442 |
6 | 20231440425 |
7 | 3050206562 |
oct | 735517441 |
9 | 281545888 |
10 | 125214497 |
11 | 64753561 |
12 | 35b26115 |
13 | 1cc31525 |
14 | 128b6169 |
15 | aed58d2 |
hex | 7769f21 |
125214497 has 2 divisors, whose sum is σ = 125214498. Its totient is φ = 125214496.
The previous prime is 125214493. The next prime is 125214539. The reversal of 125214497 is 794412521.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 80712256 + 44502241 = 8984^2 + 6671^2 .
It is a cyclic number.
It is not a de Polignac number, because 125214497 - 22 = 125214493 is a prime.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (125214493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62607248 + 62607249.
It is an arithmetic number, because the mean of its divisors is an integer number (62607249).
Almost surely, 2125214497 is an apocalyptic number.
It is an amenable number.
125214497 is a deficient number, since it is larger than the sum of its proper divisors (1).
125214497 is an equidigital number, since it uses as much as digits as its factorization.
125214497 is an evil number, because the sum of its binary digits is even.
The product of its digits is 20160, while the sum is 35.
The square root of 125214497 is about 11189.9283733186. The cubic root of 125214497 is about 500.2858325683.
The spelling of 125214497 in words is "one hundred twenty-five million, two hundred fourteen thousand, four hundred ninety-seven".
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