Base | Representation |
---|---|
bin | 111010010011101101… |
… | …1001111011111001100 |
3 | 102222012111001200102120 |
4 | 1310213123033133030 |
5 | 4022420132114312 |
6 | 133305002452540 |
7 | 12021646140252 |
oct | 1644733173714 |
9 | 388174050376 |
10 | 125215504332 |
11 | 49115984786 |
12 | 20326504150 |
13 | ba6689b2c9 |
14 | 60bbca45d2 |
15 | 33cccca28c |
hex | 1d276cf7cc |
125215504332 has 24 divisors (see below), whose sum is σ = 292522821696. Its totient is φ = 41688028368.
The previous prime is 125215504291. The next prime is 125215504333. The reversal of 125215504332 is 233405512521.
125215504332 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a super-3 number, since 3×1252155043323 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 125215504293 and 125215504302.
It is not an unprimeable number, because it can be changed into a prime (125215504333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6298798 + ... + 6318645.
It is an arithmetic number, because the mean of its divisors is an integer number (12188450904).
Almost surely, 2125215504332 is an apocalyptic number.
125215504332 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
125215504332 is an abundant number, since it is smaller than the sum of its proper divisors (167307317364).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
125215504332 is a wasteful number, since it uses less digits than its factorization.
125215504332 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12618277 (or 12618275 counting only the distinct ones).
The product of its (nonzero) digits is 36000, while the sum is 33.
The spelling of 125215504332 in words is "one hundred twenty-five billion, two hundred fifteen million, five hundred four thousand, three hundred thirty-two".
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