Base | Representation |
---|---|
bin | 10111010100101100… |
… | …10001101010001001 |
3 | 1012022122200100111222 |
4 | 23222112101222021 |
5 | 201121020031013 |
6 | 5430302131425 |
7 | 622204130513 |
oct | 135226215211 |
9 | 35278610458 |
10 | 12521642633 |
11 | 5346160495 |
12 | 2515580b75 |
13 | 12472568c6 |
14 | 86b008bb3 |
15 | 4d4461508 |
hex | 2ea591a89 |
12521642633 has 2 divisors, whose sum is σ = 12521642634. Its totient is φ = 12521642632.
The previous prime is 12521642611. The next prime is 12521642657. The reversal of 12521642633 is 33624612521.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10500510784 + 2021131849 = 102472^2 + 44957^2 .
It is a cyclic number.
It is not a de Polignac number, because 12521642633 - 210 = 12521641609 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12521642593 and 12521642602.
It is not a weakly prime, because it can be changed into another prime (12521642933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6260821316 + 6260821317.
It is an arithmetic number, because the mean of its divisors is an integer number (6260821317).
Almost surely, 212521642633 is an apocalyptic number.
It is an amenable number.
12521642633 is a deficient number, since it is larger than the sum of its proper divisors (1).
12521642633 is an equidigital number, since it uses as much as digits as its factorization.
12521642633 is an evil number, because the sum of its binary digits is even.
The product of its digits is 51840, while the sum is 35.
The spelling of 12521642633 in words is "twelve billion, five hundred twenty-one million, six hundred forty-two thousand, six hundred thirty-three".
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