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1252211655137 is a prime number
BaseRepresentation
bin10010001110001101101…
…000011000000111100001
311102201011210011000002112
4102032031220120013201
5131004012140431022
62355131425325105
7156316654306652
oct22161550300741
94381153130075
101252211655137
1144307291a403
1218282b196795
139111060a0c1
144487088b529
152288d8008e2
hex1238da181e1

1252211655137 has 2 divisors, whose sum is σ = 1252211655138. Its totient is φ = 1252211655136.

The previous prime is 1252211655073. The next prime is 1252211655151. The reversal of 1252211655137 is 7315561122521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1165587981376 + 86623673761 = 1079624^2 + 294319^2 .

It is a cyclic number.

It is not a de Polignac number, because 1252211655137 - 26 = 1252211655073 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1252211655094 and 1252211655103.

It is not a weakly prime, because it can be changed into another prime (1252211655157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626105827568 + 626105827569.

It is an arithmetic number, because the mean of its divisors is an integer number (626105827569).

Almost surely, 21252211655137 is an apocalyptic number.

It is an amenable number.

1252211655137 is a deficient number, since it is larger than the sum of its proper divisors (1).

1252211655137 is an equidigital number, since it uses as much as digits as its factorization.

1252211655137 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 126000, while the sum is 41.

Adding to 1252211655137 its reverse (7315561122521), we get a palindrome (8567772777658).

The spelling of 1252211655137 in words is "one trillion, two hundred fifty-two billion, two hundred eleven million, six hundred fifty-five thousand, one hundred thirty-seven".