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12522656753713 is a prime number
BaseRepresentation
bin1011011000111010100010…
…0000011110100000110001
31122100011011110222011020101
42312032220200132200301
53120132400112104323
642344455030112401
72431506052063411
oct266165040364061
948304143864211
1012522656753713
113a989132aa747
1214a2b844ab701
136cab5c7696b2
14314157ca0641
1516ab22b60dad
hexb63a881e831

12522656753713 has 2 divisors, whose sum is σ = 12522656753714. Its totient is φ = 12522656753712.

The previous prime is 12522656753707. The next prime is 12522656753723. The reversal of 12522656753713 is 31735765622521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6666605228529 + 5856051525184 = 2581977^2 + 2419928^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12522656753713 is a prime.

It is not a weakly prime, because it can be changed into another prime (12522656753723) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6261328376856 + 6261328376857.

It is an arithmetic number, because the mean of its divisors is an integer number (6261328376857).

Almost surely, 212522656753713 is an apocalyptic number.

It is an amenable number.

12522656753713 is a deficient number, since it is larger than the sum of its proper divisors (1).

12522656753713 is an equidigital number, since it uses as much as digits as its factorization.

12522656753713 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 15876000, while the sum is 55.

The spelling of 12522656753713 in words is "twelve trillion, five hundred twenty-two billion, six hundred fifty-six million, seven hundred fifty-three thousand, seven hundred thirteen".