Base | Representation |
---|---|
bin | 10010001110010011101… |
… | …011110101001110110011 |
3 | 11102201102212021020112112 |
4 | 102032103223311032303 |
5 | 131004214141132430 |
6 | 2355145454315535 |
7 | 156322326525302 |
oct | 22162353651663 |
9 | 4381385236475 |
10 | 1252313224115 |
11 | 443115192708 |
12 | 1828591b8bab |
13 | 9112867caa5 |
14 | 4488016a439 |
15 | 228976b5195 |
hex | 12393af53b3 |
1252313224115 has 16 divisors (see below), whose sum is σ = 1516882896000. Its totient is φ = 992489336832.
The previous prime is 1252313224079. The next prime is 1252313224157. The reversal of 1252313224115 is 5114223132521.
It is a cyclic number.
It is not a de Polignac number, because 1252313224115 - 28 = 1252313223859 is a prime.
It is a super-2 number, since 2×12523132241152 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2484290 + ... + 2945559.
It is an arithmetic number, because the mean of its divisors is an integer number (94805181000).
Almost surely, 21252313224115 is an apocalyptic number.
1252313224115 is a deficient number, since it is larger than the sum of its proper divisors (264569671885).
1252313224115 is a wasteful number, since it uses less digits than its factorization.
1252313224115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5430286.
The product of its digits is 14400, while the sum is 32.
Adding to 1252313224115 its reverse (5114223132521), we get a palindrome (6366536356636).
The spelling of 1252313224115 in words is "one trillion, two hundred fifty-two billion, three hundred thirteen million, two hundred twenty-four thousand, one hundred fifteen".
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