Base | Representation |
---|---|
bin | 100101001101011111101… |
… | …1100111111111101101001 |
3 | 200002220201000002110111212 |
4 | 1022122333130333331221 |
5 | 1132242412110220041 |
6 | 14513235222402505 |
7 | 1035330134240246 |
oct | 112327734777551 |
9 | 20086630073455 |
10 | 5114223132521 |
11 | 16a1a256a3638 |
12 | 6a7206b90435 |
13 | 2b13664a9049 |
14 | 13975b7a45cd |
15 | 8d0754678eb |
hex | 4a6bf73ff69 |
5114223132521 has 2 divisors, whose sum is σ = 5114223132522. Its totient is φ = 5114223132520.
The previous prime is 5114223132509. The next prime is 5114223132527. The reversal of 5114223132521 is 1252313224115.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2589267174400 + 2524955958121 = 1609120^2 + 1589011^2 .
It is a cyclic number.
It is not a de Polignac number, because 5114223132521 - 218 = 5114222870377 is a prime.
It is not a weakly prime, because it can be changed into another prime (5114223132527) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2557111566260 + 2557111566261.
It is an arithmetic number, because the mean of its divisors is an integer number (2557111566261).
Almost surely, 25114223132521 is an apocalyptic number.
It is an amenable number.
5114223132521 is a deficient number, since it is larger than the sum of its proper divisors (1).
5114223132521 is an equidigital number, since it uses as much as digits as its factorization.
5114223132521 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 14400, while the sum is 32.
Adding to 5114223132521 its reverse (1252313224115), we get a palindrome (6366536356636).
The spelling of 5114223132521 in words is "five trillion, one hundred fourteen billion, two hundred twenty-three million, one hundred thirty-two thousand, five hundred twenty-one".
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