125240131 has 2 divisors, whose sum is σ = 125240132. Its totient is φ = 125240130.

The previous prime is 125240033. The next prime is 125240179. The reversal of 125240131 is 131042521.

It is a strong prime.

It is an emirp because it is prime and its reverse (131042521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 125240131 - 2²¹ = 123142979 is a prime.

It is a super-2 number, since 2×125240131² = 31370180825794322, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 125240099 and 125240108.

It is not a weakly prime, because it can be changed into another prime (125240831) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62620065 + 62620066.

It is an arithmetic number, because the mean of its divisors is an integer number (62620066).

Almost surely, 2^125240131 is an apocalyptic number.

125240131 is a deficient number, since it is larger than the sum of its proper divisors (1).

125240131 is an equidigital number, since it uses as much as digits as its factorization.

125240131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 240, while the sum is 19.

The square root of 125240131 is about 11191.0737197107. The cubic root of 125240131 is about 500.3199698616.

Adding to 125240131 its reverse (131042521), we get a palindrome (256282652).

The spelling of 125240131 in words is "one hundred twenty-five million, two hundred forty thousand, one hundred thirty-one".