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12524402013 = 34174800671
BaseRepresentation
bin10111010101000001…
…10011010101011101
31012022211212112200020
423222200303111131
5201122221331023
65430441222353
7622236442404
oct135240632535
935284775606
1012524402013
115347775672
1225164919b9
1312479b1886
1486b52663b
154d4808de3
hex2ea83355d

12524402013 has 4 divisors (see below), whose sum is σ = 16699202688. Its totient is φ = 8349601340.

The previous prime is 12524401997. The next prime is 12524402029. The reversal of 12524402013 is 31020442521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (12524401997) and next prime (12524402029).

It is a cyclic number.

It is not a de Polignac number, because 12524402013 - 24 = 12524401997 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12524407013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2087400333 + ... + 2087400338.

It is an arithmetic number, because the mean of its divisors is an integer number (4174800672).

Almost surely, 212524402013 is an apocalyptic number.

It is an amenable number.

12524402013 is a deficient number, since it is larger than the sum of its proper divisors (4174800675).

12524402013 is an equidigital number, since it uses as much as digits as its factorization.

12524402013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4174800674.

The product of its (nonzero) digits is 1920, while the sum is 24.

Adding to 12524402013 its reverse (31020442521), we get a palindrome (43544844534).

The spelling of 12524402013 in words is "twelve billion, five hundred twenty-four million, four hundred two thousand, thirteen".

Divisors: 1 3 4174800671 12524402013